The largest 4-digit number exactly divisible by 12, 15, 18 and 27 is. View Solution. Q 4. Find the greatest number of 6 digits exactly divisible by 24, 15 and 36. View Solution. Q 5. The smallest number of 4-digits exactly divisible by 12,15,20 and 35 is. View Solution.
find the largest 4 digit number which when divided by 4,7an 13 leaves a remainder of 3 in each case. view solution. q2.
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For example, if you know that a > b is true, from that single comparison you should realize that a is no longer a candidate for the smallest, while b is no longer a candidate for the largest. Basically, with 4 numbers, two tests a > b and c > d already clearly separate the numbers into two candidates for the largest and two candidates for the
The largest 4-digit number exactly divisible by 12, 15, 18 and 27 is. Q. The largest 5 digit number exactly divisible by 91 is: Q.
Input: Q [] = {4, 3, 1} Output: 1009 9973. 101 997. 1 7. Approach: D digit numbers start from 10(D – 1) and end at 10D – 1. Now, the task is to find the smallest and the largest prime number from this range. To answer a number of queries for prime numbers, Sieve of Eratosthenes can be used to answer whether a number is prime or not.
The greatest number of four digit is 9999. LCM of 24, 36 and 54 = 2 × 2 × 2 × 3 × 3 × 3 = 216 The greatest number of.The correct option is C 9600. Greatest number of 4− digits is 9999. Now, 15 =3×5. 25 =5×5. 40 = 2×2×2×5. and 75 = 3×5×5. L.C.M. of 15,25,40 and 75 is 2×2×2×3×5×5= 600. On dividing 9999 by 600, the remainder is 399. Required number = (9999−399) =9600 .
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Transcript. Example 11 Find the greatest 4-digit number which is a perfect square. Greatest 4-digit number = Finding Square root of 9999 by Long Division Here, Remainder = 198 Since remainder is not 0, So, 9999 is not a perfect square We need to find the greatest 4-digit number which is a perfect square So, we need to find a number smaller than 9999, as numbers bigger than 9999 are 5 digit
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